Selecting all today’s records

Dave — Tue, 23 Feb 2010 07:53:39 +0000

Dates can be difficult to work with especially when you are not interested in the time portion. So here’s a quick snippet that strips the time portion out of the equation, making it easy to get only today’s records (or any day for that matter).

SELECT Column1,Column2, Datestamp FROM tblExample

WHERE DATEADD(day, DATEDIFF(day, 0, GetDate()), 0) = DATEADD(day, DATEDIFF(day, 0, Datestamp), 0)

SQL 2000 Find and Replace

Dave — Wed, 01 Jul 2009 10:40:42 +0000

I needed to find and replace text in a text field in sql2000… here’s how I got it right:

declare @StringToReplace varchar(1000)
SET @StringToReplace =‘baad string’

declare @NewString varchar(1000)

SET @NewString = ‘new improved string’

declare @start int

declare @end int

SELECT @end = len(@StringToReplace)-2

declare @currentrecord int

declare @ptrval BINARY(16)

declare @TotalOldTextInstancesStillToBeFixed int

SELECT @TotalOldTextInstancesStillToBeFixed = count(*) FROM tblTable WHERE body LIKE @StringToReplace

while (@TotalOldTextInstancesStillToBeFixed > 0)

begin

 SELECT top 1 @currentrecord = TableID FROM tblTable WHERE body LIKE @StringToReplace ORDER BY TableID

 –select @currentrecord

 SELECT @ptrval = textptr(tblTable.body),@start = (PATINDEX(@StringToReplace, body)-1)

 FROM tblTable WHERE tblTable.TableID = @currentrecord

 –select @start,@end

 updatetext tblTable.body @ptrval @start @end @NewString

 SELECT @TotalOldTextInstancesStillToBeFixed = count(*) FROM tblTable WHERE body LIKE @StringToReplace

end

Disclaimer: test this thoroughly in a dev environment before letting it loose on your production data. Seriously.

Dave Russell » SQL

Selecting all today’s records

SQL 2000 Find and Replace